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lxc-ls: Show a simple error message when non-root

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Instead of returning a python stacktrace, check what the current euid is
and show an argparse error message similar to that used in lxc-start-ephemeral.

Signed-off-by: Stéphane Graber <stgraber@ubuntu.com>
Acked-by: Serge E. Hallyn <serge.hallyn@ubuntu.com>
This commit is contained in:
Stéphane Graber 2012-12-04 16:17:08 -05:00
parent c0b5f522fe
commit daf04e4ce9
1 changed files with 7 additions and 0 deletions
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7
src/lxc/lxc-ls
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@ -32,6 +32,7 @@ warnings.filterwarnings("ignore", "The python-lxc API isn't yet stable")
import argparse import argparse
import gettext import gettext
import lxc import lxc
import os
import re import re
import sys import sys
@ -115,6 +116,12 @@ parser.add_argument("filter", metavar='FILTER', type=str, nargs="?",
args = parser.parse_args() args = parser.parse_args()
# Basic checks
## The user needs to be uid 0
if not os.geteuid() == 0:
parser.error(_("You must be root to run this script. Try running: sudo %s"
% (sys.argv[0])))
# --active is the same as --running --frozen # --active is the same as --running --frozen
if args.active: if args.active:
if not args.state: if not args.state: