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acddc0ed3c
Done with a combination of regex'ing and banging my head against a wall. Signed-off-by: David Lamparter <equinox@opensourcerouting.org>
29 lines
705 B
Python
29 lines
705 B
Python
# SPDX-License-Identifier: GPL-2.0-or-later
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# zlog fuzz-tester input generator
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#
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# Copyright (C) 2021 David Lamparter for NetDEF, Inc.
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from itertools import chain
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import struct
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lengths = set([128])
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# lengths = [[i, i + 1, i + 3, i - 1, i - 3] for i in lengths]
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# lengths = set([i for i in chain(*lengths) if i >= 0])
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dsts = [0, 1, 2, 3]
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fmts = [0, 1, 2, 3]
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def combo():
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for l0 in lengths:
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for l1 in lengths:
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for l2 in lengths:
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for fmt in fmts:
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for dst in dsts:
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yield (l0, l1, l2, fmt, dst)
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for i, tup in enumerate(combo()):
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with open("input/i%d" % i, "wb") as fd:
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fd.write(struct.pack("HHHBB", *tup))
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