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rebase: don't ask for time sorting

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`git-rebase--merge` does not ask for time sorting, but uses the default. We now
produce the same default time-ordered output as git, so make us of that since
it's not always the same output as our time sorting.
This commit is contained in:
Carlos Martín Nieto 2016-10-05 12:57:53 +02:00
parent 82d4c0e6b8
commit 3cc5ec94f8
1 changed files with 1 additions and 1 deletions
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src/rebase.c
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@ -586,7 +586,7 @@ static int rebase_init_operations(
(error = git_revwalk_hide(revwalk, git_annotated_commit_id(upstream))) < 0) (error = git_revwalk_hide(revwalk, git_annotated_commit_id(upstream))) < 0)
goto done; goto done;
git_revwalk_sorting(revwalk, GIT_SORT_REVERSE | GIT_SORT_TIME); git_revwalk_sorting(revwalk, GIT_SORT_REVERSE);
while ((error = git_revwalk_next(&id, revwalk)) == 0) { while ((error = git_revwalk_next(&id, revwalk)) == 0) {
if ((error = git_commit_lookup(&commit, repo, &id)) < 0) if ((error = git_commit_lookup(&commit, repo, &id)) < 0)