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commands/pgp: Format code for grub_error() is incorrect
The format code is for a 32-bit int, but the argument, keyid, is declared as a 64 bit int. The comment above says keyid is 32-bit. I'm not sure if the comment or declaration is wrong, so force the display of a 64-bit int for now. Signed-off-by: Glenn Washburn <development@efficientek.com> Reviewed-by: Daniel Kiper <daniel.kiper@oracle.com>
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@ -633,8 +633,8 @@ grub_verify_signature_real (struct grub_pubkey_context *ctxt,
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if (!sk)
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{
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/* TRANSLATORS: %08x is 32-bit key id. */
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grub_error (GRUB_ERR_BAD_SIGNATURE, N_("public key %08x not found"),
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keyid);
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grub_error (GRUB_ERR_BAD_SIGNATURE,
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N_("public key %08" PRIxGRUB_UINT64_T " not found"), keyid);
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goto fail;
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}
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